Source code for dipy.tracking.learning

"""Learning algorithms for tractography"""

import numpy as np

import dipy.tracking.distances as pf


[docs] def detect_corresponding_tracks(indices, tracks1, tracks2): """Detect corresponding tracks from list tracks1 to list tracks2 where tracks1 & tracks2 are lists of tracks Parameters ---------- indices : sequence of indices of tracks1 that are to be detected in tracks2 tracks1 : sequence of tracks as arrays, shape (N1,3) .. (Nm,3) tracks2 : sequence of tracks as arrays, shape (M1,3) .. (Mm,3) Returns ------- track2track : array (N,2) where N is len(indices) of int it shows the correspondence in the following way: the first column is the current index in tracks1 the second column is the corresponding index in tracks2 Examples -------- >>> import numpy as np >>> import dipy.tracking.learning as tl >>> A = np.array([[0, 0, 0], [1, 1, 1], [2, 2, 2]]) >>> B = np.array([[1, 0, 0], [2, 0, 0], [3, 0, 0]]) >>> C = np.array([[0, 0, -1], [0, 0, -2], [0, 0, -3]]) >>> bundle1 = [A, B, C] >>> bundle2 = [B, A] >>> indices = [0, 1] >>> arr = tl.detect_corresponding_tracks(indices, bundle1, bundle2) Notes ----- To find the corresponding tracks we use mam_distances with 'avg' option. Then we calculate the argmin of all the calculated distances and return it for every index. (See 3rd column of arr in the example given below.) """ li = len(indices) track2track = np.zeros((li, 2)) cnt = 0 for i in indices: rt = [pf.mam_distances(tracks1[i], t, "avg") for t in tracks2] rt = np.array(rt) track2track[cnt] = np.array([i, rt.argmin()]) cnt += 1 return track2track.astype(int)
[docs] def detect_corresponding_tracks_plus(indices, tracks1, indices2, tracks2): """Detect corresponding tracks from 1 to 2 where tracks1 & tracks2 are sequences of tracks Parameters ---------- indices : sequence of indices of tracks1 that are to be detected in tracks2 tracks1 : sequence of tracks as arrays, shape (N1,3) .. (Nm,3) indices2 : sequence of indices of tracks2 in the initial brain tracks2 : sequence of tracks as arrays, shape (M1,3) .. (Mm,3) Returns ------- track2track : array (N,2) where N is len(indices) of int showing the correspondence in th following way the first column is the current index of tracks1 the second column is the corresponding index in tracks2 Examples -------- >>> import numpy as np >>> import dipy.tracking.learning as tl >>> A = np.array([[0, 0, 0], [1, 1, 1], [2, 2, 2]]) >>> B = np.array([[1, 0, 0], [2, 0, 0], [3, 0, 0]]) >>> C = np.array([[0, 0, -1], [0, 0, -2], [0, 0, -3]]) >>> bundle1 = [A, B, C] >>> bundle2 = [B, A] >>> indices = [0, 1] >>> indices2 = indices >>> arr = tl.detect_corresponding_tracks_plus(indices, bundle1, indices2, bundle2) Notes ----- To find the corresponding tracks we use mam_distances with 'avg' option. Then we calculate the argmin of all the calculated distances and return it for every index. (See 3rd column of arr in the example given below.) See Also -------- distances.mam_distances """ li = len(indices) track2track = np.zeros((li, 2)) cnt = 0 for i in indices: rt = [pf.mam_distances(tracks1[i], t, "avg") for t in tracks2] rt = np.array(rt) track2track[cnt] = np.array([i, indices2[rt.argmin()]]) cnt += 1 return track2track.astype(int)